3-[x-(3+x)]=x-1

Solution for 3-[x-(3+x)]=x-1 equation:

Simplifying
3 + -1[x + -1(3 + x)] = x + -1
3 + -1[x + (3 * -1 + x * -1)] = x + -1
3 + -1[x + (-3 + -1x)] = x + -1

Reorder the terms:
3 + -1[-3 + x + -1x] = x + -1

Combine like terms: x + -1x = 0
3 + -1[-3 + 0] = x + -1
3 + -1[-3] = x + -1

Multiply -1 * -3
3 + 3 = x + -1

Combine like terms: 3 + 3 = 6
6 = x + -1

Reorder the terms:
6 = -1 + x

Solving
6 = -1 + x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x' to each side of the equation.
6 + -1x = -1 + x + -1x

Combine like terms: x + -1x = 0
6 + -1x = -1 + 0
6 + -1x = -1

Add '-6' to each side of the equation.
6 + -6 + -1x = -1 + -6

Combine like terms: 6 + -6 = 0
0 + -1x = -1 + -6
-1x = -1 + -6

Combine like terms: -1 + -6 = -7
-1x = -7

Divide each side by '-1'.
x = 7

Simplifying
x = 7